Attempt the Following Questions. Answers with explanations are given at the end.
1. It was calculated
that 75 men could complete a piece of work in 20 days. When work was scheduled
to commence, it was found necessary to send 25 men to another project. How much
longer will it take to complete the work?
2. A student divided a number by 2/3 when
he required to multiply by 3/2. Calculate the percentage of error in his
result.
3. A dishonest shopkeeper professes to
sell pulses at the cost price, but he uses a false weight of 950gm. for a kg.
His gain is …%.
4. A software engineer has the capability
of thinking 100 lines of code in five minutes and can type 100 lines of code in
10 minutes. He takes a break for five minutes after every ten minutes. How many
lines of codes will he complete typing after an hour?
5. A man was engaged on a job for 30 days
on the condition that he would get a wage of Rs. 10 for the day he works, but
he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at
the end, he was absent for work for ... days.
6. A contractor agreeing to finish a work
in 150 days, employed 75 men each working 8 hours daily. After 90 days, only
2/7 of the work was completed. Increasing the number of men by ________ each
working now for 10 hours daily, the work can be completed in time.
7. what is a percent of b divided by b percent of a?
(a) a (b) b (c) 1 (d) 10 (d) 100
8. A man bought a horse and a cart. If he
sold the horse at 10 % loss and the cart at 20 % gain, he would not lose
anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would
lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the
horse and Rs.________ for the cart.
9. A tennis marker is trying to put
together a team of four players for a tennis tournament out of seven available.
males - a, b and c; females – m, n, o and p. All players are of equal ability
and there must be at least two males in the team. For a team of four, all
players must be able to play with each other under the following restrictions:
b should not play with
m,
c should not play with
p, and
a should not play with
o.
Which of the following statements
must be false?
1.
b and p cannot be selected together
2.
c and o cannot be selected together
3.
c and n cannot be selected together.
10-12. The following figure
depicts three views of a cube. Based on this, answer questions 10-12.
6 5 
4
4
1 22 3 6
10. The number on the face opposite to the
face carrying 1 is _______ .
11. The number on the faces adjacent to the
face marked 5 are _______ .
12. Which of the following pairs does not
correctly give the numbers on the opposite faces.
(1) 6,5 (2) 4,1 (3) 1,3 (4) 4,2
13. Five farmers have 7, 9, 11, 13 & 14
apple trees, respectively in their orchards. Last year, each of them discovered
that every tree in their own orchard bore exactly the same number of apples.
Further, if the third farmer gives one apple to the first, and the fifth gives
three to each of the second and the fourth, they would all have exactly the
same number of apples. What were the yields per tree in the orchards of the
third and fourth farmers?
14. Five boys were climbing a hill. J was
following H. R was just ahead of G. K was between G & H. They were climbing
up in a column. Who was the second?
15-18 John is undecided which of the four novels to
buy. He is considering a spy
thriller, a
Murder mystery, a Gothic romance and a science fiction novel. The books are
written by Rothko, Gorky, Burchfield and Hopper, not necessary in that order,
and published by Heron, Piegon, Blueja and sparrow, not necessary in that
order.
(1) The book by Rothko is
published by Sparrow.
(2) The Spy thriller is published
by Heron.
(3) The science fiction novel is by Burchfield and is not published by
Blueja.
(4)The Gothic romance is by
Hopper.
15. Pigeon publishes ____________.
16. The novel by Gorky ________________.
17. John purchases books by the authors
whose names come first and third in alphabetical order. He does not buy the
books ______.
18. On the basis of the first paragraph and
statement (2), (3) and (4) only, it is possible to deduce that
1.
Rothko wrote the murder mystery or the spy thriller
2.
Sparrow published the murder mystery or the spy thriller
3.
The book by Burchfield is published by Sparrow.
19. If a light flashes every 6 seconds, how many times will it
flash in ¾ of an hour?
20. If point P is on line segment AB, then which of the following
is always true?
(1)
AP = PB (2) AP > PB (3) PB > AP (4) AB > AP (5) AB > AP + PB
21. All men are vertebrates. Some mammals are
vertebrates. Which of the following conclusions drawn from the above statement
is correct.
All men are mammals
All mammals are men
Some vertebrates are mammals.
None
22. Which of the following statements drawn from the given
statements are correct?
Given:
All watches sold
in that shop are of high standard. Some of the HMT watches are sold in that
shop.
a)
All watches of high standard were manufactured by HMT.
b)
Some of the HMT watches are of high standard.
c)
None of the HMT watches is of high standard.
d)
Some of the HMT watches of high standard are sold in
that shop.
23-27.
1.
Ashland is north of East Liverpool and west of
Coshocton.
2.
Bowling green is north of Ashland and west of
Fredericktown.
3.
Dover is south and east of Ashland.
4.
East Liverpool is north of Fredericktown and east of
Dover.
5.
Fredericktown is north of Dover and west of Ashland.
6.
Coshocton is south of Fredericktown and west of Dover.
23. Which of the towns mentioned is furthest of the north – west
(a)
Ashland (b) Bowling green (c) Coshocton
(d) East
Liverpool (e) Fredericktown
24. Which of the following must be both north and east of
Fredericktown?
(a)
Ashland (b) Coshocton (c) East Liverpool
I
a only II b only III c only IV a & b V
a & c
25. Which of the following towns must be
situated both south and west of at least one other town?
A.
Ashland only
B.
Ashland and Fredericktown
C.
Dover and Fredericktown
D.
Dover, Coshocton and Fredericktown
E.
Coshocton, Dover and East Liverpool.
26. Which of the following statements, if
true, would make the information in the numbered statements more specific?
(a)
Coshocton is north of Dover.
(b)
East Liverpool is north of Dover
(c)
Ashland is east of Bowling green.
(d)
Coshocton is east of Fredericktown
(e)
Bowling green is north of Fredericktown
27. Which of the numbered statements gives
information that can be deduced from one or more of the other statements?
(A) 1 (B) 2 (C)
3 (D) 4 (E) 6
28. Eight friends Harsha, Fakis, Balaji,
Eswar, Dhinesh, Chandra, Geetha, and Ahmed are sitting in a circle facing the
center. Balaji is sitting between Geetha and Dhinesh. Harsha is third to the
left of Balaji and second to the right of Ahmed. Chandra is sitting between
Ahmed and Geetha and Balaji and Eshwar are not sitting opposite to each other.
Who is third to the left of Dhinesh?
29. If every alternative letter starting from
B of the English alphabet is written in small letter, rest all are written in
capital letters, how the month “
September” be written.
(1) SeptEMbEr (2) SEpTeMBEr (3) SeptembeR
(4) SepteMber (5) None of the
above.
30. The length of the side of a square is
represented by x+2. The length of the side of an equilateral triangle is 2x. If
the square and the equilateral triangle have equal perimeter, then the value of
x is _______.
31. It takes Mr. Karthik y hours to complete
typing a manuscript. After 2 hours, he was called away. What fractional part of
the assignment was left incomplete?
32. Which of the following is larger than
3/5?
(1) ½ (2) 39/50 (3) 7/25 (4) 3/10 (5) 59/100
33. The number that does not have a
reciprocal is ____________.
34. There
are 3 persons Sudhir, Arvind, and Gauri. Sudhir lent cars to Arvind and Gauri
as many as they had already. After some time Arvind gave as many cars to Sudhir
and Gauri as many as they have. After sometime Gauri did the same thing. At the
end of this transaction each one of them had 24. Find the cars each originally
had.
35. A man bought a horse and a cart. If he
sold the horse at 10 % loss and the cart at 20 % gain, he would not lose
anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would
lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the
horse and Rs.________ for the cart.
Answers:
1. Answer:
30
days.
Explanation:
Before:
One day work = 1
/ 20
One man’s one day work = 1
/ ( 20 * 75)
Now:
No.
Of workers = 50
One
day work = 50 * 1 / ( 20 * 75)
The
total no. of days required to complete the work = (75 * 20) / 50 = 30
2. Answer:
0
%
Explanation:
Since 3x / 2 = x / (2 / 3)
3. Answer:
5.3 %
Explanation:
He
sells 950 grams of pulses and gains 50 grams.
If he sells 100 grams of pulses then
he will gain (50 / 950) *100 = 5.26
4. Answer:
250
lines of codes
5. Answer:
7
days
Explanation:
The
equation portraying the given problem is:
10 * x
– 2 * (30 – x) = 216 where x is the number of working days.
Solving
this we get x = 23
Number
of days he was absent was 7 (30-23) days.
6. Answer:
150
men.
Explanation:
One
day’s work = 2 / (7 * 90)
One
hour’s work = 2 / (7 * 90 * 8)
One
man’s work = 2 / (7 * 90 * 8 * 75)
The
remaining work (5/7) has to be completed within 60 days, because the total
number of days allotted for the project is 150 days.
So
we get the equation
(2 * 10 * x * 60) / (7 *
90 * 8 * 75) = 5/7 where x is the number of men working after
the 90th day.
We get x = 225
Since we have 75 men already, it is
enough to add only 150 men.
7. Answer:
(c)
1
Explanation:
a
percent of b : (a/100) * b
b percent of a : (b/100) * a
a percent of b divided by b percent
of a : ((a / 100 )*b) / (b/100) * a )) =
1
8. Answer:
Cost
price of horse = Rs. 400 & the cost
price of cart = 200.
Explanation:-
Let x be the cost price of the horse
and y be the cost price of the cart.
In the first sale there is no loss
or profit. (i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
X =
2 * y -----------------(1)
In the second sale, he lost Rs. 10.
(i.e.) The loss is greater than the profit by Rs. 10.
Therefore (5 / 100) * x = (5 / 100) * y + 10
-------(2)
Substituting (1) in (2)
we get
(10 / 100) *
y =
(5 / 100) * y + 10
(5 / 100) *
y =
10
y = 200
From (1) 2 * 200
= x = 400
9. Answer:
3.
Explanation:
Since
inclusion of any male player will reject a female from the team. Since there
should be four member in the team and only three males are available, the girl,
n should included in the team always irrespective of others selection.
10. Answer:
5
11. Answer:
1,2,3
& 4
12. Answer:
B
13. Answer:
11
& 9 apples per tree.
Explanation:
Let a, b, c, d & e be the total
number of apples bored per year in A, B, C, D & E ‘s orchard. Given that a + 1 = b + 3 = c – 1 = d + 3 = e – 6
But the question
is to find the number of apples bored per tree in C and D ‘s orchard. If is
enough to consider c – 1 = d + 3.
Since the number of trees in C’s
orchard is 11 and that of D’s orchard is 13. Let x and y be the number of
apples bored per tree in C & d ‘s orchard respectively.
Therefore 11 x – 1 = 13 y + 3
By trial and
error method, we get the value for x and y as 11 and 9
14. Answer:
G.
Explanation:
The order in which
they are climbing is R – G – K – H – J
15 – 18
Answer:
Novel
Name Author Publisher
Spy
thriller Rathko Heron
Murder
mystery Gorky Piegon
Gothic
romance Burchfield Blueja
Science
fiction Hopper Sparrow
Explanation:
Given
Novel
Name Author Publisher
Spy
thriller Rathko Heron
Murder
mystery Gorky Piegon
Gothic
romance Burchfield Blueja
Science
fiction Hopper Sparrow
Since
Blueja doesn’t publish the novel by Burchfield and Heron publishes the novel
spy thriller, Piegon publishes the novel by Burchfield.
Since
Hopper writes Gothic romance and Heron publishes the novel spy thriller, Blueja
publishes the novel by Hopper.
Since
Heron publishes the novel spy thriller and Heron publishes the novel by Gorky,
Gorky writes Spy thriller and Rathko writes Murder mystery.
19. Answer:
451
times.
Explanation:
There
are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾)
minutes = 45 minutes.
In
¾ of an hour there are (60 * 45) seconds = 2700 seconds.
Light flashed for every 6 seconds.
In
2700 seconds 2700/6 = 450 times.
The count start
after the first flash, the light will flashes 451 times in ¾ of an hour.
20. Answer:
(4)
Explanation:
P
A B
Since
p is a point on the line segment AB, AB > AP
21. Answer: (c)
22. Answer: (b) & (d).
Ahmed
23 - 27.Answer:
Fakis Chandra
28.
Answer: Fakis
Explanation: Harsha Geetha
Eswar Balaji
Dhinesh
29.
Answer:
(5).
Explanation:
Since
every alternative letter starting from B of the English alphabet is written in
small letter, the letters written in small letter are b, d, f...
In the first two answers the letter
E is written in both small & capital letters, so they are not the correct
answers. But in third and fourth answers the letter is written in small letter
instead capital letter, so they are not the answers.
30.
Answer:
x
= 4
Explanation:
Since the side
of the square is x + 2, its perimeter = 4 (x + 2) = 4x + 8
Since the side
of the equilateral triangle is 2x, its perimeter = 3 * 2x = 6x
Also, the
perimeters of both are equal.
(i.e.) 4x + 8 = 6x
(i.e.) 2x = 8 è x = 4.
31. Answer:
(y – 2) / y.
Explanation:
To type a manuscript karthik took y
hours.
Therefore his speed in typing = 1/y.
He was called away after 2 hours of
typing.
Therefore the work completed = 1/y *
2.
Therefore the remaining work to be
completed = 1 – 2/y.
(i.e.) work to be completed = (y-2)/y
32. Answer:
(2)
33.
Answer:
1
Explanation:
One
is the only number exists without reciprocal because the reciprocal of one is
one itself.
34.
Answer:
Sudhir
had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
Explanation:
Sudhir Arvind Gauri
Finally 24 24 24
Before Gauri’s transaction 12 12 48
Before
Arvind’s transaction 6 42 24
Before
Sudhir’ s transaction 39 21 12
35. Answer:
Cost
price of horse: Rs. 400 &
Cost
price of cart: Rs. 200
Explanation:
Let x
be the cost of horse & y be the cost of the cart.
10
% of loss in selling horse = 20 % of gain in selling the cart
Therefore (10 / 100) * x = (20 * 100) * y
è
x = 2y -----------(1)
5 % of loss in
selling the horse is 10 more than the 5 % gain in selling the cart.
Therefore (5 / 100) * x - 10 = (5 / 100) * y
è 5x - 1000 = 5y
Substituting (1)
10y - 1000 =
5y
5y = 1000
y = 200
x = 400 from
(1)
Exercise 2.1
For the following, find the next term in the series
1. 6, 24, 60,120, 210
a) 336 b) 366 c) 330 d) 660
Answer : a) 336
Explanation : The series is 1.2.3, 2.3.4, 3.4.5, 4.5.6, 5.6.7,
..... ( '.' means product)
2. 1, 5, 13, 25
Answer : 41
Explanation : The series is of the form 0^2+1^2, 1^2+2^2,...
3. 0, 5, 8, 17
Answer : 24
Explanation : 1^2-1, 2^2+1, 3^2-1, 4^2+1, 5^2-1
4. 1, 8, 9, 64, 25 (Hint : Every successive terms are related)
Answer : 216
Explanation : 1^2, 2^3, 3^2, 4^3, 5^2, 6^3
5. 8,24,12,36,18,54
Answer : 27
6. 71,76,69,74,67,72
Answer : 67
7. 5,9,16,29,54
Answer : 103
Explanation : 5*2-1=9; 9*2-2=16; 16*2-3=29; 29*2-4=54; 54*2-5=103
8. 1,2,4,10,16,40,64 (Successive
terms are related)
Answer : 200
Explanation : The series is powers of 2 (2^0,2^1,..).
All digits are less than 8. Every second number is in octal number
system.
128 should follow 64. 128 base 10 =
200 base 8.
Exercise 2.2
Find the odd man out.
1. 3,5,7,12,13,17,19
Answer : 12
Explanation : All but 12 are odd
numbers
2. 2,5,10,17,26,37,50,64
Answer : 64
Explanation : 2+3=5; 5+5=10; 10+7=17; 17+9=26; 26+11=37;
37+13=50; 50+15=65;
3. 105,85,60,30,0,-45,-90
Answer : 0
Explanation : 105-20=85; 85-25=60;
60-30=30; 30-35=-5; -5-40=-45; -45-45=-90;
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