Sample Questions for IBM Aptitude Test With Answers (Part - II)

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Check these too Part - I>>  Part - III >> 

1. The rate of color toner increases $33 to $35 and rate of black&white toner increases $28 to $29. If company spends $1540 in which 3/5 is color toner then how much is total expenditure increases after the cost hike.
Ans.  Total spend amount = $1540
3/5 is color-toner = 3/5 * 1540 = $924.
Number of color toner = 924/33 = 28.
Number of black and white toner = 22.
Total expenditure after hike= 28*35 + 22*29 = $1618.
Increase in total expenditure = 1618-1540 = $78.

2. A printer started its work at 8.15 a.m and ended its work at 9.20 p.m. It was interrupted twice for the time duration of 42 min. It can print 100 instructions per hour. Approximate how many instructions it can print?
Ans.  Time duration from 8.15am to 9.20pm = 13 hours 5 min = 785 minutes
stoppage for 2*42 min= 84 min
effective running time = 701 min
in 60 min 100 instructions are printed
in 1 min = 100/60 instructions
in 701 min , we have 701*100/ 60 = 1168.33 instructions

3. If a company produces 15 different model of tv sets of 2 inches screen and 4 different model of 4 inches screen size. Then how many model should vendor has for all the model so that all models will displayed in the showroom.
Ans. 15 models of 2 inches screen =15
4 models of 4 inches screen = 4
 15+4= 19

4. In A,B,C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A,B,and C have equal number of marbles.

If the total number of marbles are 72, then the number of marbles with A at the starting
(a) 20
(b) 30
(c) 32
(d) 39
Ans. go from the end.
at end each having equal no.of marbles.
totally we have 72 marbles.
so at end all are having 24,24,24.
previous step C gave A and B the same number of marbles they already have...
A     B     C
24   24    24
if c gave same amount means in previous steps it look like
12 12 48
if b gave same amount means in previous steps it look like
6 42 24
so intially a gave to b and c
39 12 12

5. Rs 50000 is divided into two parts One part is given to a person with 10% interest and another part is given to a person with 20 % interest. At the end of first year he gets profit 7000 Find money given by 10%?
Ans.  let x was given to a with 10% interest.
then b got 50,000 - x
interest = p*t*r /100
7000 =((50000 - x)*1*20)/100 +(x*1*10)/100
700000 = 1000000 - 10x
x = 30000

6. The price of sugar increases by 20%, by what % house-wife should
reduce the consumption of sugar so that expenditure on sugar can be
same as before
Ans. As price increase and consumption are inversely proportional,
if one increases by 1/x then other should reduce by 1/(x+1)
hence 20% is 1/5, consumption should reduce by 1/6 = 16.66%

7. Machine A is got for rent and maintatence cost of 250$ is spent per month. Another machine B is purchased for 1500$ and cost of maintenance is 75$ per month. what is the expenditure difference?
Ans. (250*12) - (1500+75*12)

8. A computer shop consists 3 brand’s laptop .Laptop of brand A is sold 3/16, B is sold 1/16 and c is sold ¾ then what fraction is sold by the shop in all.
Ans. A+B+C = 3/16 + 1/16 + 3/4 = 3/16 + 1/16 + 12/16 = 16/16.
A+B+C = 1
A,B, and C make up 100% of the laptops.

9. If a car starts from A towards B with some velocity. Due to some problem in the engine after traveling 30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actual time. If the car engine fails after traveling 45km, the car reaches the destination B 36min late to the actual time What is the initial velocity of car and what is the distance between A and B in km
Ans.  let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=> 4x-12y=120 ----(1).
45/y + (x-45)5/4y -x/y=3/5
=> 5x-12y=225 -------(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25 km/hr
and Distance From A to B is 105 km

10. Person A can finish 2/5 of work and person B can finish 3/5 of work. If A completed some 1/9 of his work and B completed 5/18 of his work. what fraction of work is not yet completed by both?
Ans.  Total work is 2/5+3/5=1
so, A use to do 2/5th work ,but he has completed =2/5*1/9 = 2/45 work
II,y B use to do 3/5th work ,but he has completed =3/5*5/18= 1/6work
left out work = 1-(2/45 +1/6)= 10/9


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