1. The rate of color toner increases $33 to
$35 and rate of black&white toner increases $28 to $29. If company spends
$1540 in which 3/5 is color toner then how much is total expenditure increases
after the cost hike.

Ans. Total spend amount = $1540

3/5
is color-toner = 3/5 * 1540 = $924.

Number
of color toner = 924/33 = 28.

Number
of black and white toner = 22.

Total
expenditure after hike= 28*35 + 22*29 = $1618.

Increase
in total expenditure = 1618-1540 = $78.

2. A printer started its work at 8.15 a.m and ended its work at 9.20 p.m. It was interrupted twice for the time duration of 42 min. It can print 100 instructions per hour. Approximate how many instructions it can print?

Ans. Time duration from 8.15am to 9.20pm = 13 hours 5 min = 785 minutes

stoppage for 2*42 min= 84 min

effective running time = 701 min

in 60 min 100 instructions are printed

in 1 min = 100/60 instructions

in 701 min , we have 701*100/ 60 = 1168.33 instructions

3. If a company produces 15 different model of tv sets of 2 inches screen and 4 different model of 4 inches screen size. Then how many model should vendor has for all the model so that all models will displayed in the showroom.

Ans. 15 models of 2 inches screen =15

4 models of 4 inches screen = 4

15+4= 19

4. In A,B,C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A,B,and C have equal number of marbles.

If the total number of marbles are 72, then the number of marbles with A at the starting

(a) 20

(b) 30

(c) 32

(d) 39

Ans. go from the end.

at end each having equal no.of marbles.

totally we have 72 marbles.

so at end all are having 24,24,24.

previous step C gave A and B the same number of marbles they already have...

so

A B C

24 24 24

if c gave same amount means in previous steps it look like

12 12 48

if b gave same amount means in previous steps it look like

6 42 24

so intially a gave to b and c

39 12 12

Ans:39:)

5. Rs 50000 is divided into two parts One
part is given to a person with 10% interest and another part is given to a
person with 20 % interest. At the end of first year he gets profit 7000 Find
money given by 10%?

Ans. let x was given to a with 10% interest.

then
b got 50,000 - x

interest
= p*t*r /100

so

7000
=((50000 - x)*1*20)/100 +(x*1*10)/100

700000
= 1000000 - 10x

x
= 30000

6. The price of sugar increases by 20%, by
what % house-wife should

reduce
the consumption of sugar so that expenditure on sugar can be

same
as before

Ans.
As price increase and consumption are inversely proportional,

if
one increases by 1/x then other should reduce by 1/(x+1)

hence
20% is 1/5, consumption should reduce by 1/6 = 16.66%

7. Machine A is got for rent and maintatence
cost of 250$ is spent per month. Another machine B is purchased for 1500$ and
cost of maintenance is 75$ per month. what is the expenditure difference?

Ans.
(250*12) - (1500+75*12)

8. A computer shop consists 3 brand’s laptop .Laptop of brand A is sold 3/16, B is sold 1/16 and c is sold ¾ then what fraction is sold by the shop in all.

Ans. A+B+C = 3/16 + 1/16 + 3/4 = 3/16 + 1/16 + 12/16 = 16/16.

A+B+C = 1

A,B, and C make up 100% of the laptops.

9. If a car starts from A towards B with
some velocity. Due to some problem in the engine after traveling 30km, the car
goes with 4/5 th of its actual velocity The car reaches B 45 min later to the
actual time. If the car engine fails after traveling 45km, the car reaches the
destination B 36min late to the actual time What is the initial velocity of car
and what is the distance between A and B in km

Ans. let x is distance from A to B

and
y is initial speed.

30/y+(x-30)5/4y
-x/y = 3/4

=>
4x-12y=120 ----(1).

45/y
+ (x-45)5/4y -x/y=3/5

=>
5x-12y=225 -------(2).

From
equ (1) and equ (2) we will get.

x=25
and y=105

so
initial speed is 25 km/hr

and
Distance From A to B is 105 km

10. Person A can finish 2/5 of work and person B can finish 3/5 of work. If A completed some 1/9 of his work and B completed 5/18 of his work. what fraction of work is not yet completed by both?

Ans. Total work is 2/5+3/5=1

so, A use to do 2/5th work ,but he has completed =2/5*1/9 = 2/45 work

II,y B use to do 3/5th work ,but he has completed =3/5*5/18= 1/6work

left out work = 1-(2/45 +1/6)= 10/9

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