Sample Questions for IBM Aptitute Test with Answers Part - I

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1.         In a computer institute 9 languages can be taught. The module is of 6 months duration and of the six languages only one can be taught each month . In addition to that BASIC is always taught and should be in first month itself
WORD PERFECT is to be taught in the preceeding week of WORD STAR. FORTRAN can not be taught until COBAL is taught prior to that BINO, FIFO can never be taught in single module languages are BASIC, WORD STAR, WORD PERFECT, FORTRAN, COBAL, BINO, FIFO, LOTUS, C
i) If word star is in 3rd month , what could be in 6th month.
ii) If COBAL is in the 2nd month and BINO in 6th month. FORTRAN will be taught in which month.

2.         The values of shares (in Rs).of A, B and C from January to June are as follows.
Month A B C
January 30 60 80
February 35 65 85
March 45 75 65
April 40 75 82
May 55 75 85
June 50 75 80
i) During this period which share has undergone maximum fluctuation?
ii) In which month it is possible to buy B and C selling A?
iii) In which month the share values are very low?
iv) By purchasing one share of A and 4 each of B and C in the beginning of the period,
when should these be sold to get maximum profit?
Ans.   i). the greatest amount by which the contract price can change, up or down, during one trading session, as fixed by exchange rules in the contract specification.
So, Answer is (C)
ii). In March, because the value of A is decrease in April, and of B and C are increase in total.
iii). January , the month in which the value of A+B+C is least.
Hence answer is
iv). value of A,B and C are highest in the month of May. Hence May is the answer.

3.         A person has Rs 100/- in his pocket, he can as 25 pencils or 15 books. He kept 15% of the money for traveling expenses and purchased 5 pencils. So how many books he can purchase with the remaining money.
Ans> cost of 15 books is 100 rupee
so cost of 3 books is 20 rupee
and cost of 25 pencils is 100 rupee
so cost of 1 pencil is 4 rupee
traveling expenses = 15 % = 15 rupee
cost of 5 pencils = 5*4 = 20 rupee
remaining amount = 100 - 35 = 65 rupee
cost of 9 books is 20*3 = 60 rupee
so total 9 books can be purchased and 5 rupee will remained.

4.         In 1978, a kg of paper was sold at Rs25/-. If the paper rate increases at 1.5% more than the inflation rate which is 6.5% a year, then what will be the cost of a kg of paper after 2 years?
(a) 29.12
(b) 29.72
(c) 30.12
(d) 32.65
(e) none of these
Ans>  If the paper rate increases at 1.5% more than the inflation rate which is 6.5%
This means paper rate increase is 1.5+6.5 = 8% per year
For the first year the increase is 8 % or (8/100)x25 = 2
So the new cost is 25+2 = 27
For the second year the increase is the same = (8/100)x27 = 2.16
So the cost = 27+2.16 = 29.16

5.         In a company printing work is done by two machine 5% of the work done by machine A are wasted , and 40% of work done by machine B are wasted. if the 80% of the total work is done by machine A. then what is the total percentage of wastage.
Ans> If total 100 units of job is done, then
80 units on machine A and 20 units of machine B.
wasted work by A = .05*80 = 4 units
wasted work by B = .4* 20 = 8 units
total wasted work = 12 units.

6.         Company A taken a truck on rent of $1280 per month another company B bought the truck in $40000 and send $120 per month. After 4 years what will be the difference in the amount spent by the both companies on the TRUCK
Ans> Difference in amt spent = 1280*48 - ( 40000+120*48)
=> 48*(1280-120)- 40000 = 48*1160-40000
=> 15680 Answer.

7.         Rectangular room has width half of its length. When 6 is decreased from both length and width then its area is differed by 108 so find the width.

Ans. Let the length be 2x, Then width will be x
The area : 2x^2
After decrease: Length(2x-6) & Width(x-6)
Now, the area:2x^2-18x+36
Hence, the eq. is 2x^2-(2x^2+18x+36)=108
Solving, we get x=8,(width)

8.         We have 171 kg rice costing 7 rs/kg.we have rice at 11 rs/kg and 2 rs/kg .then after mixing 11 rs/kg and 2 rs/kg rice. What is quantity of 11 rs/kg rice.
Ans.  A = 11 rs/kg rice
b = 2 rs/kg rice
11a= cost of 11 rs/kg rice
2b= cost of 2 rs/kg rice
a+b = 171
11a+ 2b = 7 x 171
solving above equation
a = 95 & b = 76

9.         In a library there are 5 cluster and each is having 44 books(module). In first weak 75 books are used, in second 95, in third 95 and in fourth 160 books are used.then tell how much fraction of books are used.
Ans> Total modules that can be used every week = 44*5 = 220
Total modules that can be used in 4 weeks = 4*220 = 880
modules used in 4 weeks = 75+95+95+160 = 425
fraction used = 425/880 = 0.483 or 48.3 %

10.       Printer A prints 8192 character per min and printer B prints 13862 character per min four character are equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:29 am then at what time both will have same no of words printed.
Ans. rate * time = words.
Ra = 8192/4 = 2048 words/minute.
Rb = 13862/4 = 3465.5 words/minute.
Ra(T+14) = Rb*T
=> T = 20.22
Approximately 20 minutes, 14 seconds from 7:29 or 7:49:14 AM.
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