CMC Ltd. Campus Placement Paper - III : Technical Aptitude

CMC Ltd Technical Placement Paper-3:

1)  Unix OS is a

a) multi-task

b) Mutual task

c) Multiple processes

d) a & c

2) The TV Satellite Transmission is a

a) Half-Duplex

b) Full Duplex

c) One-way duplex

d) Non of the above   

  

3) Which among is the OOPL

a) c  b) java  c) Cobol  d) Pascal

4) what will be the output of

 main()

{

int a=5,c;

int ptr;

ptr=&a;

c=*ptr * a;

printf("%d,%d",c,a);

        }

a) 5,5     b)25,25      c) 25,5      d) Error

5) What can a Friend Keyword do?

a) Free the memory

b) Provide access to private & public variables

c) Provide access to Private, Protected, public variables.

d) Never allowed to access any constructor

6)  Abstract Class can be

a) Accessed as Constructors

b) Used for hiding information of class

c) Class is Abstract class

d) None of the above

7) The present LAN-card Supports

a)32kbphs     b) 64kbphs    c)128kbphs    d) 256kbphs  

                

8) What is CDMA Technology?

a) Electronic calculator

b) Cellular phones

c) Rocket

d) Car

9) What is GC in JAVA?

a) De-allocates the memory

b) De-allocates the objects & its reference

c) Finalizing of Memory

d) Non-of the above

10 which among is thread class?

a) sleep()

b) IsAliva()

c) IsLive()

d) none of the above

11)    main()

           {

            int x=10,y=5,p,q;

            p=x>9;

            q=x>3&&y!=3;

            printf("p=%d q=%d",p,q);                                                   

           }

Ans: 1, 1

12.     main()

            {

             int x=11,y=6,z;

             z=x==5 || !=4;

             printf("z=%d",z);

           }

Ans:1

13)   main()

         {

           int c=0,d=5,e=10,a;

           a=c>1?d>1||e>1?100:200:300;

           printf("a=%d",a);

       }

Ans:300

14)  main()

      {

        int i=-5,j=-2;

        junk(i,&j);

        printf("i=%d,j=%d",i,j);

     }

        junk(i,j)

        int i,*j

       {

         i=i*i;

         *j=*j**j;

      }

  Ans: -5, 4;

15.   #define NO

       #define YES                                                                          

       main()

         {

           int i=5,j;

           if(i>5)

           j=YES;

          else

          j=NO;

         printf("%d",j);

       }

  Ans: Error message

16.   main()

         {

         int a=0xff;

         if(a<<4>>12)

         printf("leftist)

      else

        printf("rightist")

     }

Ans: rightist

17.    main ()

         {

          int i=+1;

          while(~i)

           printf("vicious circles")                                                      

        }

   Ans: continuous loop